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Popular >

foci x^2+16

Solution

foci

x^{2} + 16

Solution

(0, \frac{65}{4})

Solution steps

Rewrite

y = x^{2} + 16

in the standard form:

4 \cdot \frac{1}{4} (y - 16) = (x - 0)^{2}

(h, k) = (0, 16), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 16)

along the y-axis

(0, 16 + p)

= (0, 16 + \frac{1}{4})

Refine

(0, \frac{65}{4})

Popular Examples

foci (y-3)^2=-20(x+2)foci

(y - 3)^{2} = - 20 (x + 2)

foci-x^2+6x foci

- x^{2} + 6 x

foci+(2h^3+4h^2+5h)/h foci

+ \frac{2 h ^{3} + 4 h ^{2} + 5 h}{h}

foci y^2+20x+8y+56=0 foci

y^{2} + 20 x + 8 y + 56 = 0

foci x^2=3y foci

x^{2} = 3 y

Frequently Asked Questions (FAQ)

What is the foci x^2+16 ?
The foci x^2+16 is (0, 65/4)