What is the foci 12x^2-72x+77 ?

The foci 12x^2-72x+77 is (3,-1487/48)

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foci 12x^2-72x+77

foci

(3, - \frac{1487}{48})

Solution steps

Rewrite

y = 12 x^{2} - 72 x + 77

in the standard form

4 \cdot \frac{1}{48} (y - (- 31)) = (x - 3)^{2}

(h, k) = (3, - 31), p = \frac{1}{48}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(3, - 31)

along the y-axis

(3, - 31 + p)

= (3, - 31 + \frac{1}{48})

Refine

(3, - \frac{1487}{48})