What is the foci-2x^2-4x+y+70=0 ?

The foci-2x^2-4x+y+70=0 is (-1,-575/8)

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foci-2x^2-4x+y+70=0

foci

- 2 x^{2} - 4 x + y + 70 = 0

(- 1, - \frac{575}{8})

Solution steps

Rewrite

- 2 x^{2} - 4 x + y + 70 = 0

in the standard form

4 \cdot \frac{1}{8} (y - (- 72)) = (x - (- 1))^{2}

(h, k) = (- 1, - 72), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 1, - 72)

along the y-axis

(- 1, - 72 + p)

= (- 1, - 72 + \frac{1}{8})

Refine

(- 1, - \frac{575}{8})

y = + 0.5 (x + 2) (x - 4)

y = 2.1 + 4.4 x - 0.7 x^{2}

y = x^{2} - 10 x - 4

(x - 2)^{2} = 8 (y + 1)

x^{2} + 2