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Popular >

foci 2y^2-16x=0

Solution

foci

2 y^{2} - 16 x = 0

Solution

(2, 0)

Solution steps

Rewrite

2 y^{2} - 16 x = 0

in the standard form:

4 \cdot 2 (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 2

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + 2, 0)

Refine

(2, 0)

Popular Examples

foci y=-3x^2 foci

y = - 3 x^{2}

foci y^2-4x+6y+17=0 foci

y^{2} - 4 x + 6 y + 17 = 0

foci y=x^2-6x+5 foci

y = x^{2} - 6 x + 5

foci (x-2)^2=8(y-1)foci

(x - 2)^{2} = 8 (y - 1)

foci x^2-2x-15 foci

x^{2} - 2 x - 15

Frequently Asked Questions (FAQ)

What is the foci 2y^2-16x=0 ?
The foci 2y^2-16x=0 is (2,0)