What is the foci 5x+3y^2=0 ?

The foci 5x+3y^2=0 is (-5/12 ,0)

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foci 5x+3y^2=0

foci

(- \frac{5}{12}, 0)

Solution steps

Rewrite

5 x + 3 y^{2} = 0

in the standard form:

4 (- \frac{5}{12}) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - \frac{5}{12}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + (- \frac{5}{12}), 0)

Refine

(- \frac{5}{12}, 0)