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Popular >

foci y=ax^2

Solution

foci

y = a x^{2}

Solution

(0, \frac{1}{4 a})

Solution steps

Rewrite

y = a x^{2}

in the standard form:

4 \cdot \frac{1}{4 a} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{4 a}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + \frac{1}{4 a})

Refine

(0, \frac{1}{4 a})

Popular Examples

foci y=(2X+5)(3X-7)foci

y = (2 X + 5) (3 X - 7)

foci y= 1/2 x^2 foci

y = \frac{1}{2} x^{2}

foci y^2=5y+7x+3 foci

y^{2} = 5 y + 7 x + 3

foci y=x^2-5x-24 foci

y = x^{2} - 5 x - 24

foci x^2-1 foci

x^{2} - 1

Frequently Asked Questions (FAQ)

What is the foci y=ax^2 ?
The foci y=ax^2 is (0, 1/(4a))