What is the foci (x^2)/4+(y^2)/9 =1 ?

The foci (x^2)/4+(y^2)/9 =1 is (0,sqrt(5)),(0,-sqrt(5))

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foci (x^2)/4+(y^2)/9 =1

foci

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1

(0, 5), (0, - 5)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 3, a = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 3^{2} - 2^{2} : 5

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

y^{2} - y - x + 1 = 0

\frac{( x - 5 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{16} = 1

x^{2} = 6 y

\frac{( y - 3 ) ^{2}}{11} - \frac{( x + 1 ) ^{2}}{5} = 1

x^{2} + 2 x + y^{2} + 4 y = 20

What is the foci (x^2)/4+(y^2)/9 =1 ?
The foci (x^2)/4+(y^2)/9 =1 is (0,sqrt(5)),(0,-sqrt(5))