What is the foci (6x)/7 (4x)/3 ?

The foci (6x)/7 (4x)/3 is (0, 7/32)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (6x)/7 (4x)/3

foci

\frac{6 x}{7} \frac{4 x}{3}

(0, \frac{7}{32})

Solution steps

Rewrite

y = \frac{6 x}{7} \cdot \frac{4 x}{3}

in the standard form

4 \cdot \frac{7}{32} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{7}{32}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + \frac{7}{32})

Refine

(0, \frac{7}{32})

4 t^{2}

2 x^{2} = - y

y = - x^{2} - 6 x - 5

y^{2} = 6 x

y^{2} + 8 x - 6 y = - 25