What is the foci (x+sqrt(2))(x-sqrt(2)) ?

The foci (x+sqrt(2))(x-sqrt(2)) is (0,-7/4)

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foci (x+sqrt(2))(x-sqrt(2))

foci

(x + 2) (x - 2)

(0, - \frac{7}{4})

Solution steps

Rewrite

y = (x + 2) (x - 2)

in the standard form

4 \cdot \frac{1}{4} (y - (- 2)) = (x - 0)^{2}

(h, k) = (0, - 2), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, - 2)

along the y-axis

(0, - 2 + p)

= (0, - 2 + \frac{1}{4})

Refine

(0, - \frac{7}{4})

(y - 2)^{2} = 12 (x + 1)

y = - 3 x^{2} + 5 x

(7 - x)^{2}

4 y^{2} - 48 x - 20 y = 71

500 (0.04 - x^{2})

What is the foci (x+sqrt(2))(x-sqrt(2)) ?
The foci (x+sqrt(2))(x-sqrt(2)) is (0,-7/4)