What is the foci y=(x+314)^2 ?

The foci y=(x+314)^2 is (-314, 1/4)

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foci y=(x+314)^2

foci

y = (x + 314)^{2}

(- 314, \frac{1}{4})

Solution steps

Rewrite

y = (x + 314)^{2}

in the standard form:

4 \cdot \frac{1}{4} (y - 0) = (x - (- 314))^{2}

(h, k) = (- 314, 0), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- 314, 0)

along the y-axis

(- 314, 0 + p)

= (- 314, 0 + \frac{1}{4})

Refine

(- 314, \frac{1}{4})

(x - 1)^{2} + 2

y - 2 = (x - 1)^{2}

x^{2} + 14 x - 8 y + 65 = 0

y = 3 x^{2}

y = 9 - (x - 2)^{2}