What is the foci y=0.00225x^2+5999.9325x+0.50625 ?

The foci y=0.00225x^2+5999.9325x+0.50625 is (-1333318.33333…,111.11111…)

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foci y=0.00225x^2+5999.9325x+0.50625

foci

y = 0.00225 x^{2} + 5999.9325 x + 0.50625

(- 1333318.33333 \dots, 111.11111 \dots)

Solution steps

Rewrite

y = 0.00225 x^{2} + 5999.9325 x + 0.50625

in the standard form

4 \cdot 111.11111 \dots (y - 0) = (x - (- \frac{5999.9325}{0.0045}))^{2}

(h, k) = (- \frac{5999.9325}{0.0045}, 0), p = 111.11111 \dots

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{5999.9325}{0.0045}, 0)

along the y-axis

(- \frac{5999.9325}{0.0045}, 0 + p)

= (- \frac{5999.9325}{0.0045}, 0 + 111.11111 \dots)

Refine

(- 1333318.33333 \dots, 111.11111 \dots)

2 (x - 2)^{2}

x = 7 y^{2}

x^{2} + 12 y = 0

X^{2}

y = x^{2} + 3

What is the foci y=0.00225x^2+5999.9325x+0.50625 ?
The foci y=0.00225x^2+5999.9325x+0.50625 is (-1333318.33333…,111.11111…)