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Popular >

foci y=x^2-16

Solution

foci

y = x^{2} - 16

Solution

(0, - \frac{63}{4})

Solution steps

Rewrite

y = x^{2} - 16

in the standard form:

4 \cdot \frac{1}{4} (y - (- 16)) = (x - 0)^{2}

(h, k) = (0, - 16), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, - 16)

along the y-axis

(0, - 16 + p)

= (0, - 16 + \frac{1}{4})

Refine

(0, - \frac{63}{4})

Popular Examples

foci 2x^2-3 foci

2 x^{2} - 3

foci y^2=-20x foci

y^{2} = - 20 x

foci y=(4x^3-7x^2-11x+5)/(4x+5)foci

y = \frac{4 x ^{3} - 7 x ^{2} - 11 x + 5}{4 x + 5}

foci y=3x^2+2 foci

y = 3 x^{2} + 2

foci y=3x^2+19x-40 foci

y = 3 x^{2} + 19 x - 40

Frequently Asked Questions (FAQ)

What is the foci y=x^2-16 ?
The foci y=x^2-16 is (0,-63/4)