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Popular >

foci-x^2+5x-7

Solution

foci

- x^{2} + 5 x - 7

Solution

(\frac{5}{2}, - 1)

Solution steps

Rewrite

y = - x^{2} + 5 x - 7

in the standard form

4 (- \frac{1}{4}) (y - (- \frac{3}{4})) = (x - \frac{5}{2})^{2}

(h, k) = (\frac{5}{2}, - \frac{3}{4}), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(\frac{5}{2}, - \frac{3}{4})

along the y-axis

(\frac{5}{2}, - \frac{3}{4} + p)

= (\frac{5}{2}, - \frac{3}{4} + (- \frac{1}{4}))

Refine

(\frac{5}{2}, - 1)

Popular Examples

foci y=(6x)/7 (4x)/3 foci

y = \frac{6 x}{7} \frac{4 x}{3}

foci y=4x^2 foci

y = 4 x^{2}

foci (x-2)=3(y-5)^2 foci

(x - 2) = 3 (y - 5)^{2}

foci y=6x^2-3x5 foci

y = 6 x^{2} - 3 x 5

foci+(y-2)=3(x-5)^2 foci

+ (y - 2) = 3 (x - 5)^{2}

Frequently Asked Questions (FAQ)

What is the foci-x^2+5x-7 ?
The foci-x^2+5x-7 is (5/2 ,-1)