What is the vertices f(x)=2x^2-12x+20 ?

The vertices f(x)=2x^2-12x+20 is Minimum (3,2)

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vertices f(x)=2x^2-12x+20

vertices

Minimum (3, 2)

Solution steps

y = 2 x^{2} - 12 x + 20

The parabola parameters are:

a = 2, b = - 12, c = 20

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{( - 12 )}{2 \cdot 2}

Simplify

x_{v} = 3

Plug in

x_{v} = 3

to find the

y_{v}

value

y_{v} = 2

Therefore the parabola vertex is

(3, 2)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 2

Minimum (3, 2)

What is the vertices f(x)=2x^2-12x+20 ?
The vertices f(x)=2x^2-12x+20 is Minimum (3,2)