What is the vertices f(x)=-2x^2-20x-46 ?

The vertices f(x)=-2x^2-20x-46 is Maximum (-5,4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices f(x)=-2x^2-20x-46

vertices

f (x) = - 2 x^{2} - 20 x - 46

Maximum (- 5, 4)

Solution steps

y = - 2 x^{2} - 20 x - 46

The parabola parameters are:

a = - 2, b = - 20, c = - 46

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{( - 20 )}{2 ( - 2 )}

Simplify

x_{v} = - 5

Plug in

x_{v} = - 5

to find the

y_{v}

value

y_{v} = 4

Therefore the parabola vertex is

(- 5, 4)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = - 2

Maximum (- 5, 4)

x^{2} - 4 x + 8

y = 3 x^{2} + 30 x + 65

f (x) = - x^{2} + 3 x + 4

y = (x - 8)^{2}

y = x^{2} - 8 x + 12

What is the vertices f(x)=-2x^2-20x-46 ?
The vertices f(x)=-2x^2-20x-46 is Maximum (-5,4)