What is the vertices f(x)=-5x^2-25x-30 ?

The vertices f(x)=-5x^2-25x-30 is Maximum (-5/2 , 5/4)

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vertices f(x)=-5x^2-25x-30

vertices

f (x) = - 5 x^{2} - 25 x - 30

Maximum (- \frac{5}{2}, \frac{5}{4})

Solution steps

y = - 5 x^{2} - 25 x - 30

The parabola parameters are:

a = - 5, b = - 25, c = - 30

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{( - 25 )}{2 ( - 5 )}

Simplify

- \frac{- 25}{2 ( - 5 )} : - \frac{5}{2}

x_{v} = - \frac{5}{2}

Plug in

x_{v} = - \frac{5}{2}

to find the

y_{v}

value

y_{v} = \frac{5}{4}

Therefore the parabola vertex is

(- \frac{5}{2}, \frac{5}{4})

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = - 5

Maximum (- \frac{5}{2}, \frac{5}{4})

y = x^{2} - 6 x + 9

y = 2 x^{2} - 13 x - 7

y = (x - 1)^{2} + 1

y = - x^{2} + 2 x + 3

f (x) = 2 x^{2} + 4

What is the vertices f(x)=-5x^2-25x-30 ?
The vertices f(x)=-5x^2-25x-30 is Maximum (-5/2 , 5/4)