What is the vertices y=6x^2-7x-3 ?

The vertices y=6x^2-7x-3 is Minimum (7/12 ,-121/24)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices y=6x^2-7x-3

vertices

y = 6 x^{2} - 7 x - 3

Minimum (\frac{7}{12}, - \frac{121}{24})

Solution steps

y = 6 x^{2} - 7 x - 3

The parabola parameters are:

a = 6, b = - 7, c = - 3

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{( - 7 )}{2 \cdot 6}

Simplify

x_{v} = \frac{7}{12}

Plug in

x_{v} = \frac{7}{12}

to find the

y_{v}

value

y_{v} = - \frac{121}{24}

Therefore the parabola vertex is

(\frac{7}{12}, - \frac{121}{24})

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 6

Minimum (\frac{7}{12}, - \frac{121}{24})

f (x) = 4 + 12 x - 3 x^{2}

f (x) = - 5 x^{2} - 25 x - 30

y = x^{2} - 6 x + 9

y = 2 x^{2} - 13 x - 7

y = (x - 1)^{2} + 1

What is the vertices y=6x^2-7x-3 ?
The vertices y=6x^2-7x-3 is Minimum (7/12 ,-121/24)