Solution
vertices
Solution
Solution steps
Rewrite in the standard form
Therefore parabola properties are:
Graph
Popular Examples
vertices f(x)=x^2+5x-2vertices x^2+6x+3y+2=0vertices y=-x^2+8x-7vertices-3x^2+6x+5vertices f(x)=-x^2+12x-35
Frequently Asked Questions (FAQ)
What is the vertices y^2+12x-2y-11=0 ?
The vertices y^2+12x-2y-11=0 is (h,k)=(1,1),p=-3