en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices+y^2=28x

Solution

vertices

+ y^{2} = 28 x

Solution

(h, k) = (0, 0), p = 7

Solution steps

y^{2} = 28 x

Rewrite

y^{2} = 28 x

in the standard form:

4 \cdot 7 (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 7

Popular Examples

vertices x^2-5x+4 vertices

x^{2} - 5 x + 4

vertices (y+3)^2=4(x-3)vertices

(y + 3)^{2} = 4 (x - 3)

vertices y=7x^2-10x+5 vertices

y = 7 x^{2} - 10 x + 5

vertices f(x)=-x^2+x vertices

f (x) = - x^{2} + x

vertices (x+2)^2-9 vertices

(x + 2)^{2} - 9

Frequently Asked Questions (FAQ)

What is the vertices+y^2=28x ?
The vertices+y^2=28x is (h,k)=(0,0),p=7