What is the vertices-2x^2+12x-20 ?

The vertices-2x^2+12x-20 is Maximum (3,-2)

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vertices-2x^2+12x-20

vertices

- 2 x^{2} + 12 x - 20

Maximum (3, - 2)

Solution steps

y = - 2 x^{2} + 12 x - 20

The parabola parameters are:

a = - 2, b = 12, c = - 20

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{12}{2 ( - 2 )}

Simplify

- \frac{12}{2 ( - 2 )} : 3

x_{v} = 3

Plug in

x_{v} = 3

to find the

y_{v}

value

y_{v} = - 2

Therefore the parabola vertex is

(3, - 2)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = - 2

Maximum (3, - 2)

y^{2} + 2 x + 6 y + 17 = 0

f (x) = 2 x^{2} + 3 x + 1

- (x + 2)^{2} + 6

f (x) = 2 x^{2} + 3 x - 5

y = - 4 (x - 2)^{2} + 4