What is the vertices x(x-4) ?

The vertices x(x-4) is Minimum (2,-4)

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vertices x(x-4)

vertices

x (x - 4)

Minimum (2, - 4)

Solution steps

y = x (x - 4)

y = x (x - 4)

The parabola parameters are:

a = 1, m = 0, n = 4

x_{v} = \frac{m + n}{2}

x_{v} = \frac{0 + 4}{2}

Simplify

x_{v} = 2

Plug in

x_{v} = 2

to find the

y_{v}

value

y_{v} = - 4

Therefore the parabola vertex is

(2, - 4)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 1

Minimum (2, - 4)

f (x) = x^{2} - 8 x + 9

y = 3 x^{2} + 9 x + 9

f (x) = x^{2} + 10 x + 7

f (x) = x^{2} - 3 x - 18

- 2 x + x (x - 2) - 2 x (x - 1) - (x - 3)