Solution
vertices
Solution
Solution steps
Rewrite in the standard form
Therefore parabola properties are:
Graph
Popular Examples
vertices 4y^2+9y^2+32x-18y+37=0vertices x^2+3x+2vertices y=+(x-3)^2vertices 3(x-6)^2+1vertices f(x)=(x+3)^2-2
Frequently Asked Questions (FAQ)
What is the vertices y^2-8y+4x=0 ?
The vertices y^2-8y+4x=0 is (h,k)=(4,4),p=-1