Solution

vertices

Solution

Solution steps
Rewrite in the standard form
Therefore parabola properties are:

Graph

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Popular Examples

vertices f(x)=(x-4)^2-4vertices x^2+8x+12vertices y=+x^2-2x-6vertices f(x)=x^2-8xvertices+3x^2+x+5

Frequently Asked Questions (FAQ)

  • What is the vertices y^2+14y+4x+45=0 ?

    The vertices y^2+14y+4x+45=0 is (h,k)=(1,-7),p=-1