What is the vertices-2.318+0.2356x-0.002674x^2 ?

The vertices-2.318+0.2356x-0.002674x^2 is Maximum (44.05385…,2.87154…)

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vertices-2.318+0.2356x-0.002674x^2

vertices

- 2.318 + 0.2356 x - 0.002674 x^{2}

Maximum (44.05385 \dots, 2.87154 \dots)

Solution steps

y = - 2.318 + 0.2356 x - 0.002674 x^{2}

Rewrite

y = - 2.318 + 0.2356 x - 0.002674 x^{2}

in the form

y = a x^{2} + b x + c

y = - 0.002674 x^{2} + 0.2356 x - 2.318

The parabola parameters are:

a = - 0.002674, b = 0.2356, c = - 2.318

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{0.2356}{2 ( - 0.002674 )}

Simplify

- \frac{0.2356}{2 ( - 0.002674 )} : 44.05385 \dots

x_{v} = 44.05385 \dots

Plug in

x_{v} = 44.05385 \dots

to find the

y_{v}

value

y_{v} = 2.87154 \dots

Therefore the parabola vertex is

(44.05385 \dots, 2.87154 \dots)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = - 0.002674

Maximum (44.05385 \dots, 2.87154 \dots)

y = 4 x^{2} + 5 x - 7

y = x^{2} + x + 8

x = - \frac{1}{4} (y + 2)^{2}

2 x^{2} - 4 x + 7

x^{2} - 5 x - 84

What is the vertices-2.318+0.2356x-0.002674x^2 ?
The vertices-2.318+0.2356x-0.002674x^2 is Maximum (44.05385…,2.87154…)