{
"query": {
"display": "vertices $$3x^{2}+2x+1$$",
"symbolab_question": "CONIC#vertices 3x^{2}+2x+1"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Parabola",
"subTopic": "vertices",
"default": "\\mathrm{Minimum}\\:(-\\frac{1}{3},\\frac{2}{3})",
"meta": {
"showVerify": true
}
},
"methods": [
{
"method": "Find vertex using polynomial form",
"query": {
"display": "vertex quadratic $$y=3x^{2}+2x+1$$",
"symbolab_question": "vertexquadratic y=3x^{2}+2x+1"
}
},
{
"method": "Find vertex using parabola form",
"query": {
"display": "vertex parabola $$y=3x^{2}+2x+1$$",
"symbolab_question": "vertexparabola y=3x^{2}+2x+1"
}
},
{
"method": "Find vertex using vertex form",
"query": {
"display": "vertex form $$y=3x^{2}+2x+1$$",
"symbolab_question": "vertexform y=3x^{2}+2x+1"
}
}
],
"steps": {
"type": "interim",
"title": "Parabola vertex given $$y=3x^{2}+2x+1:{\\quad}$$Minimum $$\\left(-\\frac{1}{3},\\:\\frac{2}{3}\\right)$$",
"input": "y=3x^{2}+2x+1",
"steps": [
{
"type": "definition",
"title": "Parabola equation in polynomial form",
"text": "The vertex of an up-down facing parabola of the form $$y=ax^2+bx+c\\:$$is $$x_{v}=-\\frac{b}{2a}$$"
},
{
"type": "step",
"primary": "The parabola parameters are:",
"result": "a=3,\\:b=2,\\:c=1"
},
{
"type": "step",
"primary": "$$x_{v}=-\\frac{b}{2a}$$",
"result": "x_{v}=-\\frac{2}{2\\cdot\\:3}"
},
{
"type": "interim",
"title": "Simplify $$-\\frac{2}{2\\cdot\\:3}:{\\quad}-\\frac{1}{3}$$",
"input": "-\\frac{2}{2\\cdot\\:3}",
"result": "x_{v}=-\\frac{1}{3}",
"steps": [
{
"type": "step",
"primary": "Multiply the numbers: $$2\\cdot\\:3=6$$",
"result": "=-\\frac{2}{6}"
},
{
"type": "step",
"primary": "Cancel the common factor: $$2$$",
"result": "=-\\frac{1}{3}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
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}
},
{
"type": "interim",
"title": "Plug in $$x_{v}=-\\frac{1}{3}\\:$$to find the $$y_{v}\\:$$value",
"input": "y_{v}=3\\left(-\\frac{1}{3}\\right)^{2}+2\\left(-\\frac{1}{3}\\right)+1",
"result": "y_{v}=\\frac{2}{3}",
"steps": [
{
"type": "interim",
"title": "Simplify $$3\\left(-\\frac{1}{3}\\right)^{2}+2\\left(-\\frac{1}{3}\\right)+1:{\\quad}\\frac{2}{3}$$",
"input": "3\\left(-\\frac{1}{3}\\right)^{2}+2\\left(-\\frac{1}{3}\\right)+1",
"result": "y_{v}=\\frac{2}{3}",
"steps": [
{
"type": "step",
"primary": "Remove parentheses: $$\\left(-a\\right)=-a$$",
"result": "=3\\left(-\\frac{1}{3}\\right)^{2}-2\\cdot\\:\\frac{1}{3}+1"
},
{
"type": "interim",
"title": "$$3\\left(-\\frac{1}{3}\\right)^{2}=\\frac{1}{3}$$",
"input": "3\\left(-\\frac{1}{3}\\right)^{2}",
"steps": [
{
"type": "interim",
"title": "$$\\left(-\\frac{1}{3}\\right)^{2}=\\frac{1}{3^{2}}$$",
"input": "\\left(-\\frac{1}{3}\\right)^{2}",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$\\left(-a\\right)^{n}=a^{n},\\:$$if $$n$$ is even",
"secondary": [
"$$\\left(-\\frac{1}{3}\\right)^{2}=\\left(\\frac{1}{3}\\right)^{2}$$"
],
"result": "=\\left(\\frac{1}{3}\\right)^{2}"
},
{
"type": "step",
"primary": "Apply exponent rule: $$\\left(\\frac{a}{b}\\right)^{c}=\\frac{a^{c}}{b^{c}}$$",
"result": "=\\frac{1^{2}}{3^{2}}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Apply rule $$1^{a}=1$$",
"secondary": [
"$$1^{2}=1$$"
],
"result": "=\\frac{1}{3^{2}}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
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}
},
{
"type": "step",
"result": "=3\\cdot\\:\\frac{1}{3^{2}}"
},
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{1\\cdot\\:3}{3^{2}}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$1\\cdot\\:3=3$$",
"result": "=\\frac{3}{3^{2}}"
},
{
"type": "step",
"primary": "Cancel the common factor: $$3$$",
"result": "=\\frac{1}{3}"
}
],
"meta": {
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"interimType": "Solver",
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}
},
{
"type": "interim",
"title": "$$2\\cdot\\:\\frac{1}{3}=\\frac{2}{3}$$",
"input": "2\\cdot\\:\\frac{1}{3}",
"steps": [
{
"type": "step",
"primary": "Multiply fractions: $$a\\cdot\\frac{b}{c}=\\frac{a\\:\\cdot\\:b}{c}$$",
"result": "=\\frac{1\\cdot\\:2}{3}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$1\\cdot\\:2=2$$",
"result": "=\\frac{2}{3}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
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}
},
{
"type": "step",
"result": "=\\frac{1}{3}-\\frac{2}{3}+1"
},
{
"type": "interim",
"title": "Combine the fractions $$\\frac{1}{3}-\\frac{2}{3}:{\\quad}-\\frac{1}{3}$$",
"result": "=-\\frac{1}{3}+1",
"steps": [
{
"type": "step",
"primary": "Apply rule $$\\frac{a}{c}\\pm\\frac{b}{c}=\\frac{a\\pm\\:b}{c}$$",
"result": "=\\frac{1-2}{3}"
},
{
"type": "step",
"primary": "Subtract the numbers: $$1-2=-1$$",
"result": "=\\frac{-1}{3}"
},
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{-a}{b}=-\\frac{a}{b}$$",
"result": "=-\\frac{1}{3}"
}
],
"meta": {
"interimType": "LCD Top Title 1Eq"
}
},
{
"type": "step",
"primary": "Convert element to fraction: $$1=\\frac{1\\cdot\\:3}{3}$$",
"result": "=\\frac{1\\cdot\\:3}{3}-\\frac{1}{3}"
},
{
"type": "step",
"primary": "Since the denominators are equal, combine the fractions: $$\\frac{a}{c}\\pm\\frac{b}{c}=\\frac{a\\pm\\:b}{c}$$",
"result": "=\\frac{1\\cdot\\:3-1}{3}"
},
{
"type": "interim",
"title": "$$1\\cdot\\:3-1=2$$",
"input": "1\\cdot\\:3-1",
"steps": [
{
"type": "step",
"primary": "Multiply the numbers: $$1\\cdot\\:3=3$$",
"result": "=3-1"
},
{
"type": "step",
"primary": "Subtract the numbers: $$3-1=2$$",
"result": "=2"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7NgJleVMs0UCBhOVqEk7Ycd6GQqufR6tr2vPxOUv7H+9hLZhL3VORCH2mYsYpGjlNP/n/sT8Hudl/0KJRqY9qee021l+wa5+se0sDbP/2KgY="
}
},
{
"type": "step",
"result": "=\\frac{2}{3}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7D/BGy1bWboSwO4M7q3mxzUvGIsTFh/OJc6yvI2aBGy/mzHVlU2rAjSf0VUOaH95KA585Wz2Y8ioMtXlAhbC3efMXbR2RE4IDn3zdYG7zid0UmHg+iQxGlGxKWDb8ymJzHimBRYRqHSWeJkuUPhfTCwQgBTCJEGzvprPB0upy4NytsglcecNQSZ3XxyJpr+uRAbROZ2EWOmlhD4bFxzWnuQ=="
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}
],
"meta": {
"interimType": "Plug In Value 2Eq"
}
},
{
"type": "step",
"primary": "Therefore the parabola vertex is",
"result": "\\left(-\\frac{1}{3},\\:\\frac{2}{3}\\right)"
},
{
"type": "step",
"primary": "If $$a<0,\\:$$then the vertex is a maximum value<br/>If $$a>0,\\:$$then the vertex is a minimum value<br/>$$a=3$$",
"result": "\\mathrm{Minimum}\\:\\left(-\\frac{1}{3},\\:\\frac{2}{3}\\right)"
}
],
"meta": {
"solvingClass": "Parabola"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\frac{(x-(-\\frac{1}{3}))^{2}}{4\\frac{1}{12}}+\\frac{2}{3}",
"displayFormula": "4\\frac{1}{12}(y-\\frac{2}{3})=(x-(-\\frac{1}{3}))^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
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}
},
{
"evalFormula": "y=\\frac{7}{12}",
"displayFormula": "y=\\frac{7}{12}",
"attributes": {
"color": "GRAY",
"lineType": "NORMAL",
"labels": [
"\\mathrm{directrix}"
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"pointsToDraw": {
"pointsLatex": [
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"pointsDecimal": [
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"attributes": [
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"labelTypes": [
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"functionChanges": [
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"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "4\\cdot \\frac{1}{12}(y-\\frac{2}{3})=(x-(-\\frac{1}{3}))^{2}",
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"localBoundingBox": {
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Solution
vertices
Solution
Solution steps
The parabola parameters are:
Simplify
Plug in to find the value
Therefore the parabola vertex is
If then the vertex is a maximum value
If then the vertex is a minimum value
Graph
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Frequently Asked Questions (FAQ)
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