{
"query": {
"display": "vertices $$x=2y^{2}$$",
"symbolab_question": "CONIC#vertices x=2y^{2}"
},
"solution": {
"level": "PERFORMED",
"subject": "Geometry",
"topic": "Parabola",
"subTopic": "vertices",
"default": "(h,k)=(0,0),p=\\frac{1}{8}",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "Parabola vertex given $$x=2y^{2}:{\\quad}\\left(h,\\:k\\right)=\\left(0,\\:0\\right),\\:p=\\frac{1}{8}$$",
"input": "x=2y^{2}",
"steps": [
{
"type": "definition",
"title": "Parabola standard equation",
"text": "$$4p\\left(x-h\\right)=\\left(y-k\\right)^{2}\\:$$ is the standard equation for a right-left facing parabola with vertex at $$\\left(h,\\:k\\right),\\:$$<br/>and a focal length $$|p|$$"
},
{
"type": "interim",
"title": "Rewrite $$x=2y^{2}\\:$$in the standard form:$${\\quad}4\\cdot\\:\\frac{1}{8}\\left(x-0\\right)=\\left(y-0\\right)^{2}$$",
"input": "x=2y^{2}",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$2$$",
"result": "\\frac{x}{2}=\\frac{2y^{2}}{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "\\frac{x}{2}=y^{2}"
},
{
"type": "step",
"primary": "Factor $$4$$",
"result": "4\\cdot\\:\\frac{\\frac{1}{2}}{4}x=y^{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "4\\cdot\\:\\frac{1}{8}x=y^{2}"
},
{
"type": "step",
"primary": "Rewrite as",
"result": "4\\cdot\\:\\frac{1}{8}\\left(x-0\\right)=\\left(y-0\\right)^{2}"
}
],
"meta": {
"interimType": "Parabola Canonical Format Title 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7XyLbZXp+Wbh+m4tF03n6J0XM44gknaY680cf47uq2RbsP/qQDlxeeNYW1ZWJxYAcfPwccPk04ro5gYDy4dxVexA0wxnGmkHWdrtVslPpf+0Q9qdJcuJZcQHTduTfqiU/2Bt1eN7EiQ/vAPIAU2YV9IdEeJB8NSwK2cnf2Bc1WE3bdeLci9PfzmQBgUrYJA7Exrr2x+sFdLUVfadGcXUhNKJlmCzQhfXMb5TwB3CtdANH/gdAmLUqfyKIm7sC2NYG"
}
},
{
"type": "step",
"primary": "Therefore parabola properties are:",
"result": "\\left(h,\\:k\\right)=\\left(0,\\:0\\right),\\:p=\\frac{1}{8}"
}
],
"meta": {
"solvingClass": "Parabola"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"funcsToDraw": {
"funcs": [
{
"evalFormula": "y=\\sqrt{4\\frac{1}{8}x}+0",
"displayFormula": "4\\frac{1}{8}x=y^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "y=-\\sqrt{4\\frac{1}{8}x}+0",
"displayFormula": "4\\frac{1}{8}x=y^{2}",
"attributes": {
"color": "PURPLE",
"lineType": "NORMAL",
"isAsymptote": false
}
},
{
"evalFormula": "x=-\\frac{1}{8}",
"displayFormula": "x=-\\frac{1}{8}",
"attributes": {
"color": "GRAY",
"lineType": "NORMAL",
"labels": [
"\\mathrm{directrix}"
],
"isAsymptote": false
}
}
]
},
"pointsToDraw": {
"pointsLatex": [
"(0,0)",
"(\\frac{1}{8},0)"
],
"pointsDecimal": [
{
"fst": 0,
"snd": 0
},
{
"fst": 0.125,
"snd": 0
}
],
"attributes": [
{
"color": "PURPLE",
"labels": [
"\\mathrm{vertex}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
},
{
"color": "PURPLE",
"labels": [
"\\mathrm{focus}"
],
"labelTypes": [
"DEFAULT"
],
"labelColors": [
"PURPLE"
]
}
]
},
"functionChanges": [
{
"origFormulaLatex": [],
"finalFormulaLatex": [],
"plotTitle": "4\\cdot \\frac{1}{8}(x)=y^{2}",
"paramsLatex": [],
"paramsReplacementsLatex": []
}
],
"localBoundingBox": {
"xMin": -1.40625,
"xMax": 1.40625,
"yMin": -1.40625,
"yMax": 1.40625
}
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
vertices
Solution
Solution steps
Rewrite in the standard form:
Therefore parabola properties are:
Graph
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Frequently Asked Questions (FAQ)
What is the vertices x=2y^2 ?
The vertices x=2y^2 is (h,k)=(0,0),p= 1/8