What is the vertices 7x^2-40x-25 ?

The vertices 7x^2-40x-25 is Minimum (20/7 ,-575/7)

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vertices 7x^2-40x-25

vertices

7 x^{2} - 40 x - 25

Minimum (\frac{20}{7}, - \frac{575}{7})

Solution steps

y = 7 x^{2} - 40 x - 25

The parabola parameters are:

a = 7, b = - 40, c = - 25

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{( - 40 )}{2 \cdot 7}

Simplify

- \frac{- 40}{2 \cdot 7} : \frac{20}{7}

x_{v} = \frac{20}{7}

Plug in

x_{v} = \frac{20}{7}

to find the

y_{v}

value

y_{v} = - \frac{575}{7}

Therefore the parabola vertex is

(\frac{20}{7}, - \frac{575}{7})

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 7

Minimum (\frac{20}{7}, - \frac{575}{7})

f (x) = (x - 3)^{2} - 1

f (x) = x^{2} + 6 x + 7

y = 2 x^{2} - 12 x + 23

f (x) = (x - 3)^{2} + 2

y = x^{2} - 2 x + 3

What is the vertices 7x^2-40x-25 ?
The vertices 7x^2-40x-25 is Minimum (20/7 ,-575/7)