What is the vertices 9x^2+16y^2=144 ?

The vertices 9x^2+16y^2=144 is (4,0),(-4,0)

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vertices 9x^2+16y^2=144

vertices

9 x^{2} + 16 y^{2} = 144

(4, 0), (- 4, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

9 x^{2} + 16 y^{2} = 144 :

Ellipse with center

(h, k) = (0, 0), a = 4, b = 3

(0 + 4, 0), (0 - 4, 0)

Refine

(4, 0), (- 4, 0)

x^{2} = 4 y - 2 y^{2}

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

\frac{( y + 3 ) ^{2}}{9} - \frac{( x - 2 ) ^{2}}{16} = 1

4 y^{2} + 48 x - 20 y = 71

y^{2} + 4 x = 0

What is the vertices 9x^2+16y^2=144 ?
The vertices 9x^2+16y^2=144 is (4,0),(-4,0)