What is the vertices y=x^2-5x-24 ?

The vertices y=x^2-5x-24 is Minimum (5/2 ,-121/4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices y=x^2-5x-24

vertices

y = x^{2} - 5 x - 24

Minimum (\frac{5}{2}, - \frac{121}{4})

Solution steps

y = x^{2} - 5 x - 24

The parabola parameters are:

a = 1, b = - 5, c = - 24

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{( - 5 )}{2 \cdot 1}

Simplify

x_{v} = \frac{5}{2}

Plug in

x_{v} = \frac{5}{2}

to find the

y_{v}

value

y_{v} = - \frac{121}{4}

Therefore the parabola vertex is

(\frac{5}{2}, - \frac{121}{4})

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 1

Minimum (\frac{5}{2}, - \frac{121}{4})

2 x^{2} + 5 x - 12

f (x) = - x^{2} - 4 x + 12

f (x) = 2 x^{2} - 12 x + 10

18 x - 9 x^{2} - 9

+ s^{2} + 2 s + 2

What is the vertices y=x^2-5x-24 ?
The vertices y=x^2-5x-24 is Minimum (5/2 ,-121/4)