What is the vertices f(x)=x^2+8x+7 ?

The vertices f(x)=x^2+8x+7 is Minimum (-4,-9)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

vertices f(x)=x^2+8x+7

vertices

f (x) = x^{2} + 8 x + 7

Minimum (- 4, - 9)

Solution steps

y = x^{2} + 8 x + 7

The parabola parameters are:

a = 1, b = 8, c = 7

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{8}{2 \cdot 1}

Simplify

x_{v} = - 4

Plug in

x_{v} = - 4

to find the

y_{v}

value

y_{v} = - 9

Therefore the parabola vertex is

(- 4, - 9)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 1

Minimum (- 4, - 9)

What is the vertices f(x)=x^2+8x+7 ?
The vertices f(x)=x^2+8x+7 is Minimum (-4,-9)