What is the vertices-0.5x^2-3 ?

The vertices-0.5x^2-3 is Maximum (0,-3)

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vertices-0.5x^2-3

vertices

- 0.5 x^{2} - 3

Maximum (0, - 3)

Solution steps

y = - 0.5 x^{2} - 3

The parabola parameters are:

a = - 0.5, b = 0, c = - 3

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{0}{2 ( - 0.5 )}

Simplify

x_{v} = 0

Plug in

x_{v} = 0

to find the

y_{v}

value

y_{v} = - 3

Therefore the parabola vertex is

(0, - 3)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = - 0.5

Maximum (0, - 3)

y^{2} - 8 x + 2 y + 17 = 0

y = x^{2} + 4 x + 3

y = x^{2} - 10 x + 7

y = 92 x^{2}

y = x^{2} - 2 x - 35