What is the vertices y=(x^25x8)/(x3) ?

The vertices y=(x^25x8)/(x3) is Minimum (0,0)

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vertices y=(x^25x8)/(x3)

vertices

y = \frac{x ^{2} 5 x 8}{x 3}

Minimum (0, 0)

Solution steps

y = \frac{x ^{2} \cdot 5 x \cdot 8}{x \cdot 3}

Rewrite

y = \frac{x ^{2} 5 x 8}{x 3}

in the form

y = a x^{2} + b x + c

y = \frac{40 x ^{2}}{3}

The parabola parameters are:

a = \frac{40}{3}, b = 0, c = 0

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{0}{2 ( \frac{40}{3} )}

Simplify

x_{v} = 0

Plug in

x_{v} = 0

to find the

y_{v}

value

y_{v} = 0

Therefore the parabola vertex is

(0, 0)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = \frac{40}{3}

Minimum (0, 0)

x^{2} - 4 x

t^{2} + 2 t - 48

f (x) = - x^{2} + 2 x + 8

x = y^{2} - 3

y = 12 x (x - 4)

What is the vertices y=(x^25x8)/(x3) ?
The vertices y=(x^25x8)/(x3) is Minimum (0,0)