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Popular Geometry >

vertices x=(y-3)^2

Solution

vertices

x = (y - 3)^{2}

Solution

(h, k) = (0, 3), p = \frac{1}{4}

Solution steps

x = (y - 3)^{2}

Rewrite

x = (y - 3)^{2}

in the standard form:

4 \cdot \frac{1}{4} (x - 0) = (y - 3)^{2}

Therefore parabola properties are:

(h, k) = (0, 3), p = \frac{1}{4}

Graph

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Frequently Asked Questions (FAQ)

What is the vertices x=(y-3)^2 ?
The vertices x=(y-3)^2 is (h,k)=(0,3),p= 1/4