What is the vertices 2X^2 ?

The vertices 2X^2 is Minimum (0,0)

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vertices 2X^2

vertices

2 X^{2}

Minimum (0, 0)

Solution steps

y = 2 X^{2}

The parabola parameters are:

a = 2, b = 0, c = 0

x_{v} = - \frac{b}{2 a}

X_{v} = - \frac{0}{2 \cdot 2}

Simplify

X_{v} = 0

Plug in

X_{v} = 0

to find the

y_{v}

value

y_{v} = 0

Therefore the parabola vertex is

(0, 0)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 2

Minimum (0, 0)

y = 2 x^{2} - 5 x + 5

y = 5 x^{2} + 210 x - 34775

x^{2} - 3 x - 10

y = 4 x^{2}

3 x^{2}