What is (x+2)^2+(y-4)^2=25 ?

The solution to (x+2)^2+(y-4)^2=25 is Circle with (a,b)=(-2,4),r=5

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(x+2)^2+(y-4)^2=25

(x + 2)^{2} + (y - 4)^{2} = 25

(a, b) = (- 2, 4), r = 5

Solution steps

(x + 2)^{2} + (y - 4)^{2} = 25

Rewrite

(x + 2)^{2} + (y - 4)^{2} = 25

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 4)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 2, 4), r = 5

9 x^{2} - 4 y^{2} - 72 x = 0

\frac{x ^{2}}{36} - \frac{y ^{2}}{64} = 1

9 x^{2} - 16 y^{2} = 144

2 x^{2} + 2 y^{2} - 12 x + 8 y - 24 = 0

\frac{( x - 5 ) ^{2}}{25} + \frac{( y + 3 ) ^{2}}{9} = 1

What is (x+2)^2+(y-4)^2=25 ?
The solution to (x+2)^2+(y-4)^2=25 is Circle with (a,b)=(-2,4),r=5