What is the vertices-2x^2-20x-39 ?

The vertices-2x^2-20x-39 is Maximum (-5,11)

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vertices-2x^2-20x-39

vertices

- 2 x^{2} - 20 x - 39

Maximum (- 5, 11)

Solution steps

y = - 2 x^{2} - 20 x - 39

The parabola parameters are:

a = - 2, b = - 20, c = - 39

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{( - 20 )}{2 ( - 2 )}

Simplify

x_{v} = - 5

Plug in

x_{v} = - 5

to find the

y_{v}

value

y_{v} = 11

Therefore the parabola vertex is

(- 5, 11)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = - 2

Maximum (- 5, 11)

y = 2 x^{2} + 5 x - 3

x^{2} - 5 x + 6

2 x^{2} + 3

y = x^{2} + 2 x - 8

- 3 x^{2} + 5 x