What is the vertices (2x-1)(5x-6) ?

The vertices (2x-1)(5x-6) is Minimum (17/20 ,-49/40)

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vertices (2x-1)(5x-6)

vertices

(2 x - 1) (5 x - 6)

Minimum (\frac{17}{20}, - \frac{49}{40})

Solution steps

y = (2 x - 1) (5 x - 6)

y = (2 x - 1) (5 x - 6)

The parabola parameters are:

a = 10, m = \frac{1}{2}, n = \frac{6}{5}

x_{v} = \frac{m + n}{2}

x_{v} = \frac{( \frac{1}{2} ) + ( \frac{6}{5} )}{2}

Simplify

\frac{( \frac{1}{2} ) + ( \frac{6}{5} )}{2} : \frac{17}{20}

x_{v} = \frac{17}{20}

Plug in

x_{v} = \frac{17}{20}

to find the

y_{v}

value

y_{v} = - \frac{49}{40}

Therefore the parabola vertex is

(\frac{17}{20}, - \frac{49}{40})

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 10

Minimum (\frac{17}{20}, - \frac{49}{40})

x^{2} + 2 x + 1

f (x) = x^{2} + 1

f (x) = x^{2} + 3

y = x^{2} + 3 x - 4

f (x) = - x^{2} + 6 x - 5

What is the vertices (2x-1)(5x-6) ?
The vertices (2x-1)(5x-6) is Minimum (17/20 ,-49/40)