What is (y-7.09)/(0.01)=x^2+25x ?

The solution to (y-7.09)/(0.01)=x^2+25x is Parabola with (h,k)=(-25/2 ,-25/16),p=25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(y-7.09)/(0.01)=x^2+25x

\frac{y - 7.09}{0.01} = x^{2} + 25 x

(h, k) = (- \frac{25}{2}, - \frac{25}{16}), p = 25

Solution steps

\frac{y - 7.09}{0.01} = x^{2} + 25 x

Rewrite

\frac{y - 7.09}{0.01} = x^{2} + 25 x

in the standard form

4 \cdot 25 (y - (- \frac{25}{16})) = (x - (- \frac{25}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{25}{2}, - \frac{25}{16}), p = 25

What is (y-7.09)/(0.01)=x^2+25x ?
The solution to (y-7.09)/(0.01)=x^2+25x is Parabola with (h,k)=(-25/2 ,-25/16),p=25