What is (s^2-2p+6p)/((s+2))=1 ?

The solution to (s^2-2p+6p)/((s+2))=1 is Parabola with (h,k)=(1/2 , 9/16),p=-1

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(s^2-2p+6p)/((s+2))=1

\frac{s ^{2} - 2 p + 6 p}{( s + 2 )} = 1

(h, k) = (\frac{1}{2}, \frac{9}{16}), p = - 1

Solution steps

\frac{s ^{2} - 2 p + 6 p}{s + 2} = 1

Rewrite

\frac{s ^{2} - 2 p + 6 p}{s + 2} - 1 = 0

in the standard form

4 (- 1) (p - \frac{9}{16}) = (s - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{2}, \frac{9}{16}), p = - 1

f, f (x)^{- 1} (x) = \frac{0.75}{10 - x}

T (n) = T (n - 1) + n^{2}

2 y = - 4 \cdot (x + 2)^{2} + m + 5

g (x) = - \frac{1}{2} x^{2} - 2

x, x = (t (x) + 2)^{2} + 5

What is (s^2-2p+6p)/((s+2))=1 ?
The solution to (s^2-2p+6p)/((s+2))=1 is Parabola with (h,k)=(1/2 , 9/16),p=-1