What is 20(1-x)=(y+1)(y+5) ?

The solution to 20(1-x)=(y+1)(y+5) is Parabola with (h,k)=(1/5 ,-3),p=-5

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20(1-x)=(y+1)(y+5)

20 (1 - x) = (y + 1) (y + 5)

(h, k) = (\frac{1}{5}, - 3), p = - 5

Solution steps

20 (1 - x) = (y + 1) (y + 5)

Rewrite

20 (1 - x) = (y + 1) (y + 5)

in the standard form

4 (- 5) (x - \frac{1}{5}) = (y - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{5}, - 3), p = - 5

What is 20(1-x)=(y+1)(y+5) ?
The solution to 20(1-x)=(y+1)(y+5) is Parabola with (h,k)=(1/5 ,-3),p=-5