What is ((x+5^2)/9)+(y-1)^2=1 ?

The solution to ((x+5^2)/9)+(y-1)^2=1 is Parabola with (h,k)=(-16,1),p=-1/36

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((x+5^2)/9)+(y-1)^2=1

(\frac{x + 5 ^{2}}{9}) + (y - 1)^{2} = 1

(h, k) = (- 16, 1), p = - \frac{1}{36}

Solution steps

\frac{x + 5 ^{2}}{9} + (y - 1)^{2} = 1

Rewrite

\frac{x + 5 ^{2}}{9} + (y - 1)^{2} = 1

in the standard form:

4 (- \frac{1}{36}) (x - (- 16)) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (- 16, 1), p = - \frac{1}{36}

4 x = y^{2} - 4 y

(x - 3) 2 + y^{2} = 8 y - 12

y = - 2 x^{2} - 4 x + 7

x, a r (x) c = - 2 x^{2} + 1

2 x^{2} + 4 x^{2} - 3 x + 9 y + 24 = 0

What is ((x+5^2)/9)+(y-1)^2=1 ?
The solution to ((x+5^2)/9)+(y-1)^2=1 is Parabola with (h,k)=(-16,1),p=-1/36