What is (y-4)^2=(x-3)^2+(y-2)^2 ?

The solution to (y-4)^2=(x-3)^2+(y-2)^2 is Parabola with (h,k)=(3,0),p=-1

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(y-4)^2=(x-3)^2+(y-2)^2

(y - 4)^{2} = (x - 3)^{2} + (y - 2)^{2}

(h, k) = (3, 0), p = - 1

Solution steps

(y - 4)^{2} = (x - 3)^{2} + (y - 2)^{2}

Rewrite

(y - 4)^{2} = (x - 3)^{2} + (y - 2)^{2}

in the standard form

4 (- 1) (y - 0) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, 0), p = - 1

x^{2} - y \leq 6

(y - 1)^{2} = 2 x

x^{2} - y \leq 2

x + y^{2} = 7

y \leq x^{2} - 4

What is (y-4)^2=(x-3)^2+(y-2)^2 ?
The solution to (y-4)^2=(x-3)^2+(y-2)^2 is Parabola with (h,k)=(3,0),p=-1