What is x^2-8m(x)-32x+5m(x)-8=0 ?

The solution to x^2-8m(x)-32x+5m(x)-8=0 is Parabola with (h,k)=(16,-88),p= 3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-8m(x)-32x+5m(x)-8=0

x^{2} - 8 m (x) - 32 x + 5 m (x) - 8 = 0

(h, k) = (16, - 88), p = \frac{3}{4}

Solution steps

x^{2} - 8 y - 32 x + 5 y - 8 = 0

Rewrite

x^{2} - 8 y - 32 x + 5 y - 8 = 0

in the standard form

4 \cdot \frac{3}{4} (y - (- 88)) = (x - 16)^{2}

Therefore parabola properties are:

(h, k) = (16, - 88), p = \frac{3}{4}

(x + 3)^{2} = - \frac{1}{2} (y - 1)

\frac{y}{x} + \frac{70 - y}{x + 10} = 6

x^{2} - 40 y = - 200

- y^{2} - 2 x = 4

3 y + x^{2} = 0

What is x^2-8m(x)-32x+5m(x)-8=0 ?
The solution to x^2-8m(x)-32x+5m(x)-8=0 is Parabola with (h,k)=(16,-88),p= 3/4