What is (x-33/16)^2= 8/15 (y-53265/2048) ?

The solution to (x-33/16)^2= 8/15 (y-53265/2048) is Parabola with (h,k)=(33/16 , 53265/2048),p= 2/15

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-33/16)^2= 8/15 (y-53265/2048)

(x - \frac{33}{16})^{2} = \frac{8}{15} (y - \frac{53265}{2048})

(h, k) = (\frac{33}{16}, \frac{53265}{2048}), p = \frac{2}{15}

Solution steps

(x - \frac{33}{16})^{2} = \frac{8}{15} (y - \frac{53265}{2048})

Rewrite

(x - \frac{33}{16})^{2} = \frac{8}{15} (y - \frac{53265}{2048})

in the standard form:

4 \cdot \frac{2}{15} (y - \frac{53265}{2048}) = (x - \frac{33}{16})^{2}

Therefore parabola properties are:

(h, k) = (\frac{33}{16}, \frac{53265}{2048}), p = \frac{2}{15}

x^{- 1} = \frac{x}{y}

3 x^{2} + 7 x + h (x) = 0

x^{2} + y - 49 = 0

2 x^{2} - 7 y + 24 = 0

x^{2} - 6 x - 4 y + 25 = 0

What is (x-33/16)^2= 8/15 (y-53265/2048) ?
The solution to (x-33/16)^2= 8/15 (y-53265/2048) is Parabola with (h,k)=(33/16 , 53265/2048),p= 2/15