What is 1+(4(x+1))/(x^2+8s+16)=0 ?

The solution to 1+(4(x+1))/(x^2+8s+16)=0 is Parabola with (h,k)=(-2,-2),p=-2

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1+(4(x+1))/(x^2+8s+16)=0

1 + \frac{4 ( x + 1 )}{x ^{2} + 8 s + 16} = 0

(h, k) = (- 2, - 2), p = - 2

Solution steps

1 + \frac{4 ( x + 1 )}{x ^{2} + 8 s + 16} = 0

Rewrite

1 + \frac{4 ( x + 1 )}{x ^{2} + 8 s + 16} = 0

in the standard form

4 (- 2) (s - (- 2)) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, - 2), p = - 2

3 - 2 x = \frac{5 y}{x}

4 (- \frac{5}{4}) (x - \frac{9}{2}) = (y - (- \frac{5}{2}))^{2}

- (y - 1) y = x

\frac{( x + 5 ) ^{2}}{100} + \frac{( y - 2 ^{2} )}{36} = 1

97 + a^{2} = b

What is 1+(4(x+1))/(x^2+8s+16)=0 ?
The solution to 1+(4(x+1))/(x^2+8s+16)=0 is Parabola with (h,k)=(-2,-2),p=-2