What is 36x^2+72x-132y-239=0 ?

The solution to 36x^2+72x-132y-239=0 is Parabola with (h,k)=(-1,-25/12),p= 11/12

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36x^2+72x-132y-239=0

36 x^{2} + 72 x - 132 y - 239 = 0

(h, k) = (- 1, - \frac{25}{12}), p = \frac{11}{12}

Solution steps

36 x^{2} + 72 x - 132 y - 239 = 0

Rewrite

36 x^{2} + 72 x - 132 y - 239 = 0

in the standard form

4 \cdot \frac{11}{12} (y - (- \frac{25}{12})) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - \frac{25}{12}), p = \frac{11}{12}

y^{2} - 12 x - 10 y + 37 = 0

6 x^{2} - 48 z = 0

3 y = 2 x^{2} - 16 x + 18

\frac{y}{- 6} y > 12 x + 42

x^{2} + 3 y = 3

What is 36x^2+72x-132y-239=0 ?
The solution to 36x^2+72x-132y-239=0 is Parabola with (h,k)=(-1,-25/12),p= 11/12