What is 9^2+4y^2-54x+8y+113=0 ?

The solution to 9^2+4y^2-54x+8y+113=0 is Parabola with (h,k)=(95/27 ,-1),p= 27/8

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9^2+4y^2-54x+8y+113=0

9^{2} + 4 y^{2} - 54 x + 8 y + 113 = 0

(h, k) = (\frac{95}{27}, - 1), p = \frac{27}{8}

Solution steps

9^{2} + 4 y^{2} - 54 x + 8 y + 113 = 0

Rewrite

9^{2} + 4 y^{2} - 54 x + 8 y + 113 = 0

in the standard form

4 \cdot \frac{27}{8} (x - \frac{95}{27}) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (\frac{95}{27}, - 1), p = \frac{27}{8}

x^{2} = 2 (2 y + 2) + 1

2 A^{2} + 3 B = 12

- 2 x^{2} \geq y

f (x) = - (x - 2) (x + 1)

x^{2} + 8 x + k (x) = 0

What is 9^2+4y^2-54x+8y+113=0 ?
The solution to 9^2+4y^2-54x+8y+113=0 is Parabola with (h,k)=(95/27 ,-1),p= 27/8