What is (25y^2)/(400)-(16x)/(400)= 400/400 ?

The solution to (25y^2)/(400)-(16x)/(400)= 400/400 is Parabola with (h,k)=(-25,0),p= 4/25

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(25y^2)/(400)-(16x)/(400)= 400/400

\frac{25 y ^{2}}{400} - \frac{16 x}{400} = \frac{400}{400}

(h, k) = (- 25, 0), p = \frac{4}{25}

Solution steps

\frac{25 y ^{2}}{400} - \frac{16 x}{400} = \frac{400}{400}

Rewrite

\frac{25 y ^{2}}{400} - \frac{16 x}{400} = \frac{400}{400}

in the standard form:

4 \cdot \frac{4}{25} (x - (- 25)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 25, 0), p = \frac{4}{25}

y^{(2)} - 10 x - 6 y = 16

2 y^{2} + y = x

(y + 1)^{2} = 20 (x + 1)

X^{2} + 2 X - 5 Y = 6

x^{2} - 76 x + 20 y - 100 = 0

What is (25y^2)/(400)-(16x)/(400)= 400/400 ?
The solution to (25y^2)/(400)-(16x)/(400)= 400/400 is Parabola with (h,k)=(-25,0),p= 4/25