What are the solutions to the equation solvefor x,Y(x)^2=-32x ?

The solutions to the equation solvefor x,Y(x)^2=-32x are x=0,x=-(32)/Y ;\quad Y\ne 0

Find the zeros of solvefor x,Y(x)^2=-32x

The zeros of solvefor x,Y(x)^2=-32x are x=0,x=-(32)/Y ;\quad Y\ne 0

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solve for

x, Y (x)^{2} = - 32 x

x = 0, x = - \frac{32}{Y}; Y \neq = 0

Solution steps

Y x^{2} = - 32 x

Move

32 x

to the left side

Y x^{2} + 32 x = 0

Factor

Y x^{2} + 32 x : x (x Y + 32)

x (x Y + 32) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x Y + 32 = 0

Solve

x Y + 32 = 0 : x = - \frac{32}{Y}; Y \neq = 0

The solutions to the quadratic equation are:

x = 0, x = - \frac{32}{Y}; Y \neq = 0

x^{2} + 6 x - 12 y + 21 = 0

y - 3 = - 2 (x - 1)^{2}

yy + 3 = \frac{4}{3} (x + 2)

(f (x) + 4) = x^{2}

\frac{( x + 5 ) ^{2}}{25} - \frac{( y + 1 ^{2} )}{36} = 1

What are the solutions to the equation solvefor x,Y(x)^2=-32x ?
The solutions to the equation solvefor x,Y(x)^2=-32x are x=0,x=-(32)/Y ;\quad Y\ne 0
Find the zeros of solvefor x,Y(x)^2=-32x
The zeros of solvefor x,Y(x)^2=-32x are x=0,x=-(32)/Y ;\quad Y\ne 0