10x^2-256=300f(x)ind

解

10 x^{2} - 256 = 300 f (x) in d

(h, k) = (0, - \frac{64}{75 d in}), p = \frac{15 d in}{2}

解答ステップ

10 x^{2} - 256 = 300 y in d

10 x^{2} - 256 = 300 y in d

を標準的な形式で書き換える:

4 \cdot \frac{15 d in}{2} (y - (- \frac{64}{75 d in})) = (x - 0)^{2}

ゆえに放物線の特性は:

(h, k) = (0, - \frac{64}{75 d in}), p = \frac{15 d in}{2}